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How to check if a given year is a leap year in Rust

Rust

fn main() {
    let mut year = String::new();
    println!("Enter a year: ");
    io::stdin().read_line(&mut year).expect("Failed to read line");

let year: u32 = match year.trim().parse() {
        Ok(num) => num,
        Err(_) => 0,
    };

if is_leap_year(year) {
        println!("{} is a leap year", year);
    } else {
        println!("{} is not a leap year", year);
    }

fn is_leap_year(year: u32) -> bool {
         if (year % 4 == 0 && !(year % 100 == 0)) || (year % 400 == 0) { true } else { false }  // or just return the expression directly.  I like the explicitness of the if/else though.  It's more readable to me.  But that's just me.  I'm sure there are people who would disagree with me on that point.   :)   -Rusty 2019-07-31T14:00Z-0700

}

/* The above function could also be written as follows: */

fn is_leap_year2(year: u32) -> bool { return (year % 4 == 0 && !(year % 100 == 0)) || (year % 400 == 0); }

/* Or even more concisely as follows: */

fn is_leap_year3(y: u32) -> bool { y%4==0 && !(y%100==0) || y%400==0 } // Note that this version uses single character variable names for brevity, which can be confusing and should generally be avoided in production code, but it's fine for this example because it's so short and simple.   -Rusty 2019-07-31T14:00Z-0700

/* Or even more concisely still as follows: */

fn is_leap_year4(y: u32) -> bool { y%4==0 && !y%100==0 || y%400==0 } // Note that this version uses single character variable names for brevity, which can be confusing and should generally be avoided in production code, but it's fine for this example because it's so short and simple.   -Rusty 2019-07-31T14:00Z-0700

/* Or even more concisely still as follows (note that we're using the ternary operator here): */

fn is_leap_year5(y: u32) -> bool { y%4==0 && !y%100==0 || y%400==0 ? true : false; } // Note that this version uses single character variable names for brevity, which can be confusing and should generally be avoided in production code, but it's fine for this example because it's so short and simple.   -Rusty 2019-07-31T14:00Z-0700

/* Or even more concisely still as follows (note that we're using the ternary operator here): */

fn is_leap_year6(y: u32) -> bool { y%4==0 && !y%100==0 || y%400==0 ? true : false; } // Note that this version uses single character variable names for brevity, which can be confusing and should generally be avoided in production code, but it's fine for this example because it's so short and simple.   -Rusty 2019-07-31T14:00Z-0700
}

🤖 Code Explanation

The code is asking the user to input a year, and then it is checking if the year is a leap year or not. If it is a leap year, it will print out that it is a leap year. Otherwise, it will print out that it is not a leap year.

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How to check if a given year is a leap year in Rust

Rust

🤖 Code Explanation

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