How are all leaves of a binary search tree printed in Go
Go
ðŸ¤– Code Explanation
func (n *Node) PrintInorder() {
if n == nil {
return
}
n.left.PrintInorder()
fmt.Println(n.value)
n.right.PrintInorder()
}
func main() {
n1 := &Node{1, nil, nil}
n2 := &Node{2, nil, nil}
n3 := &Node{3, nil, nil}
n4 := &Node{4, nil, nil}
n1.left = n2
n1.right = n3
n2.left = n4
n1.PrintInorder()
}
This code defines a struct for a node in a binary tree, with fields for the value stored at the node and pointers to the left and right child nodes. The code also contains a method
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